Answer by Matt L. for Sampling with an alternating impulse train
In addition to Dan's excellent answer, which gives some intuition and a nice graphical representation of what is going on, I would like to give a concise mathematical derivation that might also be...
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Answer by Dan Boschen for Sampling with an alternating impulse train
We are not simply sampling the message in this case but also multiplying by a sampled tone that exists at $f_s/2$, (where $f_s$ is the sampling rate) and therefore we are frequency shifting the signal...
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Sampling with an alternating impulse train
The have the following question:A signal $m(t)$ with bandwidth 500Hz is first multiplied by a signal$g(t)$ where $\displaystyle g(t)=\sum_{k=-\infty}^{\infty}(-1)^k \delta(t-0.5*10^{-4}k)$. The signal...
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